JavaScriotのfilterとsortについて - Qiita

const satoru = { age: 38, name: 'tanaka' }; const ken = { age: 34, name: 'yamada' }; const nozomi = { age: 30, name: 'koyama' }; const users = [ken, nozomi, satoru]; const ages = users.map(user => { const tall = user.age*5; // 年齢を5倍した数を、仮に身長の数値に見立てただけで、意味はありません。 return tall; }); const segatakaihito = ages.filter(tall => tall > 172) console.log(ages.sort().reverse()); //並び替え、背が低い順 console.log(segat