最小二乗法を用いた3次Bezier曲線あてはめ JavaScriptで - Qiita

export default _ => { const l = _.length - 1 const s = _[ 0 ] const e = _[ l ] let pp = 0, pq = 0, qp = 0, qq = 0, p = 0, q = 0 for ( let $ = 1; $ < l; $++ ) { // Bypass first and last element, because 't' or 'u' will be zero. const t = $ / l const u = 1 - t const P = 3 * u * u * t const Q = 3 * u * t * t pp += P * P qq += Q * Q const PQ = P * Q pq += PQ qp += PQ const R = _[ $ ] - u * u * u * s -