JS 配列の後ろからN個返す - Qiita

const takeRight = (array = [], takeRightNum = 1) => { if (takeRightNum === 0) { return [] } if (array.length < takeRightNum) { return [...array] } let newArray = [] for (let i = 0; i < takeRightNum; i++) { const index = array.length - (1 + i) newArray.push(array[index]) } return newArray } console.log(takeRight([1, 2, 3])) // => [3] console.log(takeRight([1, 2, 3], 2)) // => [2, 3] console.log(tak