Leetcode 263. Ugly Number - Qiita

class Solution { public boolean isUgly(int n) { if (n == 0) { return false; } if (2 <= n && n <= 6) { return true; } while (true) { if (n % 2 == 0) { n /= 2; continue; } if (n % 3 == 0) { n /= 3; continue; } if (n % 5 == 0) { n /= 5; continue; } break; } return n == 1; } } func isUgly(n int) bool { if n == 0 { return false } for { if n % 2 == 0{ n /= 2 continue } if n % 3 == 0{ n /= 3 continue } i