PHPで画像のEXIF(位置情報)を取得する方法JSON { "FileName": "photo.jpg", "FileDateTime": 0, "FileSize": 125729, "FileType": 2, "MimeType": "image/jpeg", "SectionsFound": "ANY_TAG, IFD0, COMMENT, EXIF, GPS", "COMPUTED": { "html": "width=\"800\" height=\"600\"", "Height": 600, "Width": 800, "IsColor": 1, "ByteOrderMotorola": 1, "ApertureFNumber": "f/2.4" }, "Make": "Apple", "Model": "iPhone 5", "Orientation": 1, "XResolution": "72/1", "YRe
