Get difference between two lists with Unique Entries
I have two lists in Python: temp1 = ['One', 'Two', 'Three', 'Four'] temp2 = ['One', 'Two'] Assuming the elements in each list are unique, I want to create a third list with items from the first list which are not in the second list: temp3 = ['Three', 'Four'] Are there any fast ways without cycles and checking?
How can I mimic the php urldecode function in postgresql?
Yes you can: CREATE OR REPLACE FUNCTION decode_url_part(p varchar) RETURNS varchar AS $$ SELECT convert_from(CAST(E'\\x' || string_agg(CASE WHEN length(r.m[1]) = 1 THEN encode(convert_to(r.m[1], 'SQL_ASCII'), 'hex') ELSE substring(r.m[1] from 2 for 2) END, '') AS bytea), 'UTF8') FROM regexp_matches($1, '%[0-9a-f][0-9a-f]|.', 'gi') AS r(m); $$ LANGUAGE SQL IMMUTABLE STRICT; This creates a function
Script to create individual zip files for each .txt file it finds and move them after
I need a shell script that basically does this: Searches in a folder for all the txt files, and for each one it finds, creates a individual zip file with the same of the txt file it found + .zip. After that moves the created zip file to the txt file. Basically its a script to substitute a list of txt files for its zip equivalent but keeping the same name. I've have used find to find the files that
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