"use strict"; function f(n){ if (n <= 0) { return "foo"; } return g(n - 1); } function g(n){ if (n <= 0) { return "bar"; } return f(n - 1); } return f(1e6) === "foo" && f(1e6+1) === "bar";
Node.js ES2015/ES6, ES2016 and ES2017 support
"use strict"; function f(n){ if (n <= 0) { return "foo"; } return g(n - 1); } function g(n){ if (n <= 0) { return "bar"; } return f(n - 1); } return f(1e6) === "foo" && f(1e6+1) === "bar";
Dynamically import module in TypeScript
What is the TypeScript way of loading modules dynamically (path to the module is known at runtime)? I tried this one: var x = "someplace" import a = module(x) But it seems that TypeScript compiler would like to see path as a string in import/module at compile time: $ tsc test.ts /tmp/test.ts(2,19): error TS1003: Identifier expected. /tmp/test.ts(2,20): error TS1005: ';' expected. I know I can for
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