なんども書いてるAjax送受信の雛形 - Qiita{ var hostUrl= 'https://*****.php'; //var param1 = 1; //var param2 = 10; $.ajax({ url: hostUrl, // username: "*****", // Basic認証用ユーザー名 // password: "*****", // Basic認証用パスワード type:'POST', dataType: 'json', data : {name : "hoge"}, //data : {parameter1 : param1, parameter2 : param2 }, timeout:3000, }).done(function(data) { console.log('Successful communication with API!'); console.log('ReturnParamete
