Erlang is Not Functional

Robert Fischer claims Scala is not a functional language. But if you go by his post then Erlang isn't either. ModulesFischer says In OCaml, we define a function like this:let f x = x + 1;;In Scala, though, we define the function somewhat differently:object SomeHolderObject { val f(x:int):int = { x + 1 } } Now some Erlang -module(SomeHolderModule). -export([f/1]). f(X) -> X + 1. Erlang requires a f

[kuenishi]

※欄。'Erlang is pragmatic'