python2 中类似ruby each_slice的实现 - Qiita

def each_slice(arr, n): return [arr[i:i + n] for i in range(0, len(arr), n)] print(each_slice([1, 2, 3, 4, 5], 2)) print(each_slice([1, 2, 3, 4, 5], 3)) print(each_slice([1, 2, 3, 4, 5], 4)) # => [[1, 2], [3, 4], [5]] # => [[1, 2, 3], [4, 5]] # => [[1, 2, 3, 4], [5]]