consでつないだlistは、list?関数で比較するとfalseになっちゃうわけ - Qiita

;; A list constructed via list satisfies both list? and seq? (list? (list 1 2 3)) ;; -> true (seq? (list 1 2 3)) ;; -> true ;; cons, however *looks* like a list, but is actually a Cons (list? (cons 1 '(2 3))) ;; -> false (type (cons 1 '(2 3))) ;; -> clojure.lang.Cons (seq? (cons 1 '(2 3))) ;; -> true ;; range's lazy return value is a seq, but not a list (list? (range 3)) ;; -> false (seq? (range 3